Constructive Interference Problem in the Time Domain

Click For Summary
SUMMARY

The discussion centers on the problem of determining the location of constructive interference for two waves on a string, represented by the functions Y1(x,t) = 4cos(20t-x) and Y2(x,t) = -4cos(20t+x). At time t = π/50 seconds, the superposition of these waves, |Ys| = |Y1 + Y2|, must be maximized to achieve constructive interference. The simplified equation derived for Ys is |Ys| = |4[cos(2π/5 - x) - cos(2π/5 + x)]|, which indicates that the maximum amplitude occurs when the waves are in phase.

PREREQUISITES
  • Understanding of wave functions and superposition principles
  • Familiarity with trigonometric identities and cosine functions
  • Knowledge of constructive and destructive interference concepts
  • Basic skills in solving equations involving trigonometric functions
NEXT STEPS
  • Explore the concept of phase difference in wave interference
  • Learn about the mathematical derivation of wave superposition
  • Investigate the use of graphical methods to analyze wave interference
  • Study the principles of sinusoidal functions and their amplitudes
USEFUL FOR

Students studying wave mechanics, physics educators, and anyone interested in understanding wave interference patterns and their mathematical representations.

KasraMohammad
Messages
18
Reaction score
0

Homework Statement


Two waves on a string are given by the following functions:
Y1 (x,t) = 4cos(20t-x)
Y2 (x,t) = -4cos(20t+x)
where x is in centimeters. The waves are said to interfere constructively when their superposition |Ys| = |Y1 + Y2| is a maximum and they interfere destructively when |Ys|
is a minimum.

if t = ∏/50 seconds, at what location x is the interference constructive?

Homework Equations


No particular equation relevant as far as I know.

The Attempt at a Solution


So to get a constructive interference, the summation of the two waves(|Y1 + Y2|) must be the largest possible. I plugged in the value for time, and got this simplified equation for Ys:

Ys = |4[cos(2∏/5 - x) - cos(2∏/5 + x)]|

Now i know |Ys| must be the largest it can be, and the only way i can think of of approaching this is constructing a X-Y table and seeing if there is a trend in the values, though I feel there must be an easier way to do this.
 
Physics news on Phys.org
KasraMohammad said:

Homework Statement


Two waves on a string are given by the following functions:
Y1 (x,t) = 4cos(20t-x)
Y2 (x,t) = -4cos(20t+x)
where x is in centimeters. The waves are said to interfere constructively when their superposition |Ys| = |Y1 + Y2| is a maximum and they interfere destructively when |Ys|
is a minimum.

if t = ∏/50 seconds, at what location x is the interference constructive?

Homework Equations


No particular equation relevant as far as I know.


The Attempt at a Solution


So to get a constructive interference, the summation of the two waves(|Y1 + Y2|) must be the largest possible. I plugged in the value for time, and got this simplified equation for Ys:

Ys = |4[cos(2∏/5 - x) - cos(2∏/5 + x)]|

Now i know |Ys| must be the largest it can be, and the only way i can think of of approaching this is constructing a X-Y table and seeing if there is a trend in the values, though I feel there must be an easier way to do this.

Yes, there is an easier way. If you add two sinusoidal functions that are in phase, what is the maximum amplitude that you can get?

y = Asin(∅) + Bsin(∅)

What is the amplitude of y?

So it's the same situation when you have constructive interference...
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
13K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
3
Views
3K