Continuity of g(x,y) = (xy)^1/3

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SUMMARY

The function g(x,y) = (xy)^(1/3) is continuous at the point (0,0). When evaluating the limit as (x,y) approaches (0,0), the limit L equals 0, which matches the function's value at that point. Despite this, graphical representations in tools like Maple may incorrectly suggest a discontinuity along the axes due to limitations in handling cube roots. The conclusion is that the function is indeed continuous, and further analysis is required to determine its differentiability at (0,0).

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Homework Statement



Show if the function g(x,y) = (xy)1/3 is continuous at the point (0,0)

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The Attempt at a Solution



I'm a bit confused. When I take the limit as (x,y)->(0,0) I get that L = 0, and the function is equal to 0 at (0,0), but when I plot the function in maple, it seems as if there is a discontinuity along the line x =0 and y = 0. I am ultimately trying to show if the function is differentiable at (0,0). Any help?
 
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Well, your calculations are correct. The function is continuous.

Many function graphers cannot handle the cube root well, which is likely the reason that it doesn't show up nice in maple.
 

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