Continuity on piecewise function

Wables
Messages
5
Reaction score
0

Homework Statement


[10 Marks] At which points is the following function continuous and at which point is it discontinuous. Explain the types of discontinuity at each point where the function is discontinuous. Then at each point of the discontinuity, if possible, find a value for f(x) that makes it continuous or one sided continuous.

f(x) =
-2x if -1\leqx<1
-2/(x-1) if 1<x<2
x-2 if x> 2

Homework Equations



Test continuity at point:
f(a) is defined
lim f(x) exists
x->a
lim f(x) = f(a)
x->a

Continuity at Endpoints
lim f(x) = f(a) = left continuous
x->a-
lim f(x) = f(a) = right continuous
x->a+

The Attempt at a Solution



Im thinking what I need to do, is:
Check for continuity at the points -1, 1, 2.
Then I would classify any discontinuities as either removable, jump, or infinite discontinuities.
But that last part, I am not sure what its asking?
What I have is this so far:

Discontinuous at x=1 and x=2.
At x=1: Jump discontinuity
At x=2: Jump discontinuity

Im not sure if I am supposed to do this or if its right, but I did it anyway:
At x=-1, the function is right continuous on the interval [-1, 1). The function is also continuous on (1, 2) and (2, infinity)
 
Physics news on Phys.org
Basically correct but the discontinuity at x= 1 is NOT a "jump" discontinuity:
\lim_{x\to 1^+} f(x)= \lim_{x\to 1}\frac{-2}{x- 1}= -\infty
 
Oh really? Cool! Thanks! So by stating the intervals of continuity, I satisfied the last part of the problem? Cause I was not sure what it was asking..
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top