Continuous functions with multiple variables

cappygal
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I need to find a value for f at (0,0) to make this function continuous:

f(x,y)=sqrt(x^2+y^2)/[abs(x) + abs(y)^(1/3)]

With other functions in this problem I simply took the limit .. but taking the limit gives 0/0. In single-variable calculus I would apply l'hopital's rule to this, but I'm not sure what to do with multiple variables.

I also need to do the same for:

f(x,y)=(x^2 + y^2)*ln(x^2 + 2y^2)

For this one, you get 0*0, again an indeterminant form. In single variable I would manipulate it until I got 0/0 and then apply l'hopital .. but I'm lost in multivariable.
 
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In f(x,y)=sqrt(x^2+y^2)/[abs(x) + abs(y)^(1/3)] the numerator goes to 0 faster than the denominator (e.g. along x=y); so my guess is f(0,0) = 0.

0*0 is not indet., it is 0. But ln(0) = -infty so you have -0*infty, which is indet. I don't have an answer for that one (yet).
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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