Contour Integral of 5z^4+z^3+2: Finding a Square Contour

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Homework Statement


given 5z^4+z^3+2

Homework Equations



the question asking me to find the contour integral of thi function in the
C circle of |z|=1. then how about if the Contour is a square with point [0,0][1,0][1,i][0,i] ?

The Attempt at a Solution



i have no idea abt how to do and i attempt to factor up to
z^4[5+ (1/z) +(2/z^4)] and then juz 2∏i(coefficient of 1/z) am i wrong?
and i totally no idea of my pole for the square contour [0,0][1,0][1,i][0,i], anyone pls help me !
 
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doey said:

Homework Statement


given 5z^4+z^3+2

Homework Equations



the question asking me to find the contour integral of thi function in the
C circle of |z|=1. then how about if the Contour is a square with point [0,0][1,0][1,i][0,i] ?

The Attempt at a Solution



i have no idea abt how to do and i attempt to factor up to
z^4[5+ (1/z) +(2/z^4)] and then juz 2∏i(coefficient of 1/z) am i wrong?
and i totally no idea of my pole for the square contour [0,0][1,0][1,i][0,i], anyone pls help me !

Your function doesn't have any poles. Does it?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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