Convergence of (2^(n)+3^(n))/(4^(n)+5^(n)) using the Comparison Test

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Decide (with justification) if the following series converges or diverges;

Sum(1,infinty) (2^(n)+3^(n))/(4^(n)+5^(n))

I've tried using the ratio test but I couldn't see that it was helping in any way, should I be using a different type of test for this problem? I really can't see where to start with this one.
 
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Try and think of a clever comparison to which you can apply the ratio test. E.g. (2^n+3^n)/(4^n+5^n)<=(3^n+3^n)/(4^n+4^n). See, I substituted a larger numerator and a smaller denominator?
 
So if you apply the ratio test to the (3^(n)+3^(n))/(4^(n)+4^(n)) you find that this series converges as l<1 (l=3/4?). Is it then allowable to say that the original series converges as it is less than (3^(n)+3^(n))/(4^(n)+4^(n)) and therefore the limit must be lees than the limit of the above series and hence it must converge.
 
You tell me, ok? Look up the comparison test for series and make sure all the requirements are fulfilled. It's good practice.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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