Convergence of an Improper Integral Involving Exponential Functions

SirPlus
Messages
18
Reaction score
0

Homework Statement



1.Determine the divergence/convergence of the following improper integrals by the evaluation of the limit:

\int_{0}^{∞} \frac{dx}{e^{-x} + e^{x}}




Homework Equations





The Attempt at a Solution



Let u = e^x
∴ du = e^x dx

I ended up with:

\int_{0}^{∞} \frac{u du}{u^{2} + 1}
I have no idea on how to integrate the above ...
 
Physics news on Phys.org
substitute v=u^2.
 
Hi SirPlus! :smile:
SirPlus said:
\int_{0}^{∞} \frac{dx}{e^{-x} + e^{x}}

Let u = e^x
∴ du = e^x dx

fine so far :wink:
\int_{0}^{∞} \frac{u du}{u^{2} + 1}

Sorry, but that's completely wrong (including the limits).

Start again, and this time write it out carefully step-by-step, with no short-cuts! :smile:
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top