Convergence of Infinite Series

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Homework Help Overview

The discussion revolves around the convergence of the infinite series \(\sum_{n=1}^{\infty } \frac{1}{n^{1+1/n}}\), as presented in a problem from Spivak. Participants are exploring various methods to determine convergence, including the integral test and comparison tests.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster considers the integral test but finds it challenging. They mention that comparison tests and the ratio test are inconclusive. Other participants suggest examining the limit of \(n^{1/n}\) and its implications for comparison.

Discussion Status

The conversation reflects a back-and-forth exploration of ideas, with some participants expressing initial confidence in convergence, while others challenge those assertions and prompt further investigation into appropriate comparisons. There is an ongoing examination of the limit of \(n^{1/n}\) and its relevance to the series.

Contextual Notes

Participants are grappling with the implications of the limit of \(n^{1/n}\) and are considering what series might serve as a suitable comparison. The discussion indicates uncertainty about the convergence status and the need for careful analysis.

aostraff
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I need some help on determining whether this infinite series converges (taken from Spivak for those curious):

\sum_{n=1}^{\infty } \frac{1}{n^{1+1/n}}

I would think the integral test would be most appropriate but it doesn't seem to work (because the integral seems hard). The obvious comparison tests are inconclusive and a ratio test seems inconclusive as well. I'm guessing the best idea right now would be to think of comparisons. Thanks.
 
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Your denominator is n^(1+1/n)=n*n^(1/n). Can you figure out the limit of n^(1/n)? Does that suggest a comparison?
 
Yeah it does. So it converges. Thanks.
 
aostraff said:
Yeah it does. So it converges. Thanks.

No it doesn't! What are you going to compare with? Are you sure it converges?!
 
Uh oh. I'm back to square one. I thought I had it but I was being reckless. I'm not quite sure how the existence of a limit for n^(1/n) helps me.
 
What IS the limit? The existence of a limit implies n^(1/n) has a maximum value. Can you find an M such that n^(1/n)<M. Now what series to compare with?
 
so n^(1/n) in limit goes to 1...

think about what type of sum this leaves you with as we go towards the limit

it is also< 2 for all n in the sum (actually <=3^(1/3) can show x^(1/x) decreases monotonically for lnx>1)
 
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