Converging Series and Derivative Analysis for Positive Terms

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sum(1/(n(n^2-1)^(1/2)),n=2,infinity)
first derivative <0 for x>=2
I(1/(x(x^2-1)^(1/2)),x,2,infinity)
x=secT, dx=secTtanT
I(secTtanT/(secTtanT),T) ?
 
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What is your question?
 
my book is showing this series converging to pi/6
 
ok..this integral is in basic form of I(1/(u(u^2-a^2)^(1/2)),u)=1/a sec^-1(u/a)+C
a=1
sec^-1 u
lim sec^-1x as x-> infinity =pi/2 and sec^-1 2=pi/3
pi/2-pi/3 =pi/6
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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