How Do You Convert Different Units of Measurement in Physics?

  • Thread starter Thread starter soulja101
  • Start date Start date
AI Thread Summary
To convert units in physics, understanding the relationships between different measurements is essential. For example, converting megajoules (MJ) to joules (J) involves recognizing that 1 MJ equals 1,000,000 J. Speed conversions, such as kilometers per hour (km/h) to meters per second (m/s), require multiplying by the appropriate factors: 1 km equals 1,000 m and 1 hour equals 3,600 seconds. The discussion highlights the importance of using fractions creatively to maintain unit consistency during conversions. Familiarity with metric prefixes and their definitions is crucial for accurate calculations.
soulja101
Messages
61
Reaction score
0
how do u convert the following
MJ to J
km/h to m/s
25 kN to ? (i don't know what)
 
Physics news on Phys.org
I usually use fractions. If I wanted to convert 10 ft/s to inches/min, for example, I would do:

10 ft/s * 12 inches/1 ft * 1 min/60 s = 2 inches/s

Since there are 12 inches in a foot, and 60 seconds in a minute, this is just multiplying by 1, in a creative way.

Just use this idea, and you will be converting units in no time at all.

Dorothy
 
Surely you have some idea as to how to do this.

Am I correct in reading the first to be converting MegaJoules to Joules.
You should be able to figure that out with a bit of thought.

Lets go through the conversion of \frac {km} h to \frac m s

There are 1000 m per km and 3600 s per h so

\frac {km} h \times \frac {1000m} {1km} \times \frac {1h} {3600s}

examine the units in this expression, note that km appears in both the numerator and denominator, so can be canceled, leaving only m. The same is true for h. Do the arithmetic.
 
Last edited:
lost

i ve tried all i know is a MJ a is a like 1000J a second but it doesn't work out for my answers
 
1000 J/s is a Kilo Watt. Mega is not 1000, and there is no second in kilo or in your problem.

Look in your physics book for the definitions of metric prefixes.

Dorothy
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top