Convert a derivative back to original function

[Ishtar]

Homework Statement

f'(x) = 5x^2 + 7x -3

The attempt at a solution

i divided 5 by 3 to get 5/3
added 1 to exponent of 5x^2
made 7x to 7x^2 and -3 to -3x

to get

f(x) = 5/3 x^ 3 + 7x^2 - 3xi get this answer, but is there and other way to get the original function and other possible answers (or a helpfull website related to this)

 

[christianjb]

The middle term is 7/2 x^2.

You can confirm your answer by differentiation back to f'(x).

Note that you could also add any number to your expression and you would still get the same derivative, because, e.g. d/dx 42 =0.

You're actually doing 'integration', though you may not know it yet. Wikipediate or Google it.

 

[HallsofIvy]

You said you "made 7x to 7x^2 and -3 to -3x" but you didn't do that in your answer.

Believe it or not, derivatives and "anti- derivatives" are calculus, not "pre"- calculus. I'm going to move this to the calculus homework forum.

 

[Ishtar]

oh yea, sry, and thanks for your answers