Converting Thermal Conductivity to Thermal Conduction/Resistance

AI Thread Summary
To convert thermal conductivity to thermal conductance, one must multiply the thermal conductivity value by the cross-sectional area of the material and then divide by its length. For example, with copper's thermal conductivity of 400 W/(m·K), the conductance will vary based on the wire's dimensions. Conductance increases with larger cross-sectional areas and decreases with longer lengths. Adding additional wires of the same size will double the conductance and halve the resistance. This understanding is crucial for accurate thermal management in engineering applications.
hamzaaaa
Messages
30
Reaction score
0
Hi all

I want to convert thermal conductivity to thermal conductance. The problem is with the units.

for thermal conductivity the units are [W/(m.K)] and for thermal conductance the units are [W/K]

For E.g for copper thermal conductivity is 400[W/m.K]
how can I convert it to thermal conductance?Can it be simply by multiplying it my the length of the copper wire I am using?

Any help with be really appreciated.

Thanks and Regards
Hamza
 
Engineering news on Phys.org
Hi Hamza! :smile:
hamzaaaa said:
for thermal conductivity the units are [W/(m.K)] and for thermal conductance the units are [W/K]

For E.g for copper thermal conductivity is 400[W/m.K]
how can I convert it to thermal conductance?Can it be simply by multiplying it my the length of the copper wire I am using?

Yup!

You can always rely on the units …

just multiply by the length (in metres) …

"/m" means exactly what it says :biggrin:
 
hmm.. I think you need to multiply by the cross-sectional area and then divide by the length. The conductance should decrease with increased length and increase with larger area.

Consider if you add a second wire of equal size. You would expect the conductance to increase by a factor of 2 (and resistance drop by a factor of 2).
 
oops!

davidrit said:
hmm.. I think you need to multiply by the cross-sectional area and then divide by the length. The conductance should decrease with increased length and increase with larger area.

Consider if you add a second wire of equal size. You would expect the conductance to increase by a factor of 2 (and resistance drop by a factor of 2).

oops! :redface: davidrit :smile: is right!

(I thought the thermal conductivity was of the wire, but I see now it's of the material … see http://en.wikipedia.org/wiki/Thermal_conductivity)
 
Thanks all...
very much appreciated.
I have a further query now which I have posted separately.

hxxp://www.physicsforums.com/showthread.php?t=330491
 
Thread 'Weird near-field phenomenon I get in my EM simulation'
I recently made a basic simulation of wire antennas and I am not sure if the near field in my simulation is modeled correctly. One of the things that worry me is the fact that sometimes I see in my simulation "movements" in the near field that seems to be faster than the speed of wave propagation I defined (the speed of light in the simulation). Specifically I see "nodes" of low amplitude in the E field that are quickly "emitted" from the antenna and then slow down as they approach the far...
Hello dear reader, a brief introduction: Some 4 years ago someone started developing health related issues, apparently due to exposure to RF & ELF related frequencies and/or fields (Magnetic). This is currently becoming known as EHS. (Electromagnetic hypersensitivity is a claimed sensitivity to electromagnetic fields, to which adverse symptoms are attributed.) She experiences a deep burning sensation throughout her entire body, leaving her in pain and exhausted after a pulse has occurred...
Back
Top