1. The problem statement, all variables and given/known data Convert ∫ from 0 to 3/√2 ∫ from y to √(9-y^2) of xydxdy to polar form. 2. Relevant equations x2+y2=r2 3. The attempt at a solution I found the equation x2+y^2=9 from the upper range of the second integral. So r=3. Therefore r ranges from 0 to 3. The integrand is now (rcosθ)(rsinθ)rdrdθ. I'm having trouble with the range of integration of the first integral (0 to 3/√2). From the other information, I think that the area I'm integrating is from -π/2 to π/2. This is wrong. Any hints? Thanks.