Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Cooper pairs and BCS

  1. Jun 7, 2010 #1
    Hi

    In my book it says that a Cooper pair is formed by a single electron state and its time-reversed counterpart. The way I have understood it, a Cooper pair is formed by the states

    [tex]
    \left| {k \uparrow } \right\rangle \quad \text{and} \quad \left| { - k \downarrow } \right\rangle.
    [/tex]

    Where does the time-reversal come into play?

    Best,
    Niles.
     
    Last edited: Jun 7, 2010
  2. jcsd
  3. Jun 7, 2010 #2
    Try to act with the time-reversal operator on the state [tex] \left| {k \uparrow } \right\rangle \quad [/tex] and see what you get. (You first need to look up how this operator works.)

    Edit: Okay I might as well reveal that you should get [tex]
    T\left| {k \uparrow } \right\rangle \quad = \quad \left| { - k \downarrow } \right\rangle.
    [/tex]
     
  4. Jun 7, 2010 #3
    Ahh, I see. I'll take a closer look at the operator.

    Thanks.
     
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook