kostas230
- 96
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I've been trying to come up with a oordinate free formula of Christoffel symbols. For the Christoffel symbols of the first kind it's really easy. Since
\Gamma_{\lambda\mu\nu} = \frac{1}{2}\left( g_{\mu\lambda,\nu}+g_{\nu\lambda,\mu} - g_{\mu\nu,\lambda}\right)
we can easily generalize the formula:
\Gamma\left(X,Y,Z\right) = \frac{1}{2}\left(Yg\left(X,Z\right)+Zg\left(X,Y\right)-Xg\left(Y,Z\right)\right)
How can we generalize in this way the Christoffel symbols of the second kind {\Gamma^\lambda}_{\mu\nu} = g^{\lambda\sigma}\Gamma_{\lambda\mu\nu}
I'm thinking that a way of doing it would be through some kind of contraction, but I'm not sure how since the Christoffel symbols of the first kind are not tensors to begin with.
\Gamma_{\lambda\mu\nu} = \frac{1}{2}\left( g_{\mu\lambda,\nu}+g_{\nu\lambda,\mu} - g_{\mu\nu,\lambda}\right)
we can easily generalize the formula:
\Gamma\left(X,Y,Z\right) = \frac{1}{2}\left(Yg\left(X,Z\right)+Zg\left(X,Y\right)-Xg\left(Y,Z\right)\right)
How can we generalize in this way the Christoffel symbols of the second kind {\Gamma^\lambda}_{\mu\nu} = g^{\lambda\sigma}\Gamma_{\lambda\mu\nu}
I'm thinking that a way of doing it would be through some kind of contraction, but I'm not sure how since the Christoffel symbols of the first kind are not tensors to begin with.