Coordination Number and Geometry

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The discussion revolves around calculating the minimum radius ratio for a coordination number of 8 in cubic geometry. The key equation in question is 2R + 2r = √3 l, where R is the larger ion radius, r is the smaller ion radius, and l is the cube edge length. The confusion arises from understanding how this equation relates to the geometry of the cube, particularly the diagonal. It is clarified that √3 l represents the diagonal of the cube, with larger ions at the corners and smaller ions fitting in between. Ultimately, the relationship is understood, resolving the initial confusion.
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I am trying to understand a sample problem in this text I have about materials science. The question is to calculate the minimum radius ration for a coordination number of 8. The coordination geometry is cubic. What I don't understand in this problem is one of the two equations they use to solve the for the ratio.

R is the larger ion radius, r is the smaller ion radius and l is the cube length edge.

Now what I don't get is how the book comes up with this relationship.

2R + 2r = \sqrt{3}\ l

The second expression l = 2R, I understand since the two large ions are touching each other, their radius will make up the length of the cube edge. They substitute this equation in the other and solve for \frac{r}{R} It's just that I don't understand where that first equation comes from.
 
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mathwurkz said:
I am trying to understand a sample problem in this text I have about materials science. The question is to calculate the minimum radius ration for a coordination number of 8. The coordination geometry is cubic. What I don't understand in this problem is one of the two equations they use to solve the for the ratio.

R is the larger ion radius, r is the smaller ion radius and l is the cube length edge.

Now what I don't get is how the book comes up with this relationship.

2R + 2r = \sqrt{3}\ l

The second expression l = 2R, I understand since the two large ions are touching each other, their radius will make up the length of the cube edge. They substitute this equation in the other and solve for \frac{r}{R} It's just that I don't understand where that first equation comes from.

\sqrt{3}\ l is the diagonal of the cube. Each corner is occupied by the larger ion, with the smaller ion fitting in the space between the large ions.
 
Ok. Great I understand it now. Thanks a lot OlderDan
 
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