Coriolis expression - Question about sign

AI Thread Summary
The discussion centers on the expression for Coriolis acceleration, Ac = -2ω x v, where ω represents Earth's rotation axis and v is the velocity of an object. The question raised is about the origin of the negative sign in the formula, with the understanding that it relates to the choice of reference frame, specifically between inertial and non-inertial frames. Participants clarify that the Coriolis force is only present in a rotating frame, such as Earth's, and the negative sign arises from this context. The conversation emphasizes that the sign is a result of coordinate choice rather than a fundamental property of the Coriolis effect. Understanding this distinction is crucial for correctly applying the Coriolis acceleration in physics problems.
Curious2013
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Homework Statement



Dear all

I have a question concerning the Coriolis acceleration expression. I learned it as Ac = -2ω x v, where ω is the vector which indicates the rotation axis direction of Earth and v the velocity of a body that I want to check the Coriolis effect on.

My question: where the minus sign comes from? As far as I understand, it depends on what reference frame I use (inertial or non inertial - the minus comes from the latter, like the Earth, in my conception). Am I correct?

Thanks in advance!

Homework Equations





The Attempt at a Solution

 
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Welcome to PF!

Hi Curious2013! Welcome to PF! :smile:
Curious2013 said:
I have a question concerning the Coriolis acceleration expression. I learned it as Ac = -2ω x v, where ω is the vector which indicates the rotation axis direction of Earth and v the velocity of a body that I want to check the Coriolis effect on.

My question: where the minus sign comes from? As far as I understand, it depends on what reference frame I use (inertial or non inertial - the minus comes from the latter, like the Earth, in my conception). Am I correct?

There's no Coriolis force in an inertial frame. :wink:

(same as centrifugal force)
 
The sign is solely due to the choice of coordinates. Here's a site that derives it as positive:

http://www.nws.noaa.gov/om/wind/deriv.shtml
 
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TheEtherWind said:
Here's a site that derives it as positive:

no, it derives it as negative

Coriolis force exists only in the Earth's frame (the rotating frame),

so in that frame (d2R/dt2)Earth is on one side of the equation, and everything else on the other side …

the Coriolis force then does have a negative sign :wink:
 
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