iRaid
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- 8
Homework Statement
\int cos^{2}x dx
I know that
cos^{2}x = \frac{1+cos2x}{2}
but I don't see how that helps me.
Can someone help walk me through it..
The discussion revolves around the integral of cos²(x), specifically the expression ∫cos²(x) dx. Participants are exploring the use of trigonometric identities to simplify the integral and are attempting to integrate the resulting expression.
Participants are actively engaging with the problem, offering insights and suggestions for approaches. There is a recognition of the need for substitution in the integration process, and some participants express uncertainty about the correctness of their results, indicating a productive exploration of the topic.
There is mention of a potential oversight regarding the inclusion of a constant of integration, which reflects the common challenges faced in integral calculus. The discussion also highlights the importance of verifying results against expected answers.
iRaid said:u=2x du=(1/2)dx
(1/2)∫cosudu
=(1/4)sin2x
So then..
x/2 + (1/4)sin2x
but that's not the answer..
Dick said:I think it is the correct answer. You should probably put a +C on it. Is that the problem?