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pairofstrings
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- How do I know that cosine of 1 degree is: 0.9998
Why is cos (1)° = 0.9998?
cos(60)° = ½?
Thanks.
cos(60)° = ½?
Thanks.
How is the cosine defined?Summary:: How do I know that cosine of 1 degree is: 0.9998
Why is cos (1)° = 0.9998?
cos(60)° = ½?
Thanks.
Have you tried doing a bit of trigonometry using the fact that 30 degrees is a third of a right angle?In a right-angled triangle 30 - 60 - 90, why adjacent side is given 1√3 unit, its hypotenuse 2 units and its opposite side is 1 unit?
Where did the side lengths 1, 1√3, 2 come from? If it is from Unit Circle then why adjacent side is 1√3. The radius of unit circle is 1 unit that is opposite to 30° angle. I don't see how 1√3 is a radius; there is only one radius in one unit circle!
View attachment 288065
It's hard to understand the statement.Have you tried doing a bit of trigonometry using the fact that 30 degrees is a third of a right angle?
Typically, the ##1\sqrt 3## is not considered a radius, the 2 is the radius.The radius of unit circle is 1 unit that is opposite to 30° angle. I don't see how 1√3 is a radius;
There must be an elementary proof using the trigonometry of a unit square or a circle.It's hard to understand the statement.
One thing I know is side length is minimum if the opposite angle is minimum,
Side length is maximum if the opposite angle is maximum.
Side length is moderate if the opposite angle is between max and min.
The graphs don't match.Algebra to the rescue! $$\cos 30 = \sin 60 =2\sin 30 \cos 30$$
What does that mean?The graphs don't match.
In a triangle with hypotenuse=2, the adjacent side length is 2*cos(30deg)=2*##\sqrt 3/2##=##\sqrt 3##. The opposite side is 2*sin(30deg)=2*1/2=1.All I am trying to understand is if there is a right-angled triangle 30 - 60 - 90, why adjacent side is given 1√3 unit, its hypotenuse 2 units and its opposite side is 1 unit? Where did they come from?
Prove it!In a triangle with hypotenuse=2, the adjacent side length is 2*cos(30deg)=2*##\sqrt 3/2##=##\sqrt 3##. The opposite side is 2*sin(30deg)=2*1/2=1.
What does that mean?
I tried to plot the graphs of $$\cos 30, \sin 60, 2\sin 30 \cos 30$$ $$\cos30$$ is not same as $$\sin60$$ and $$2\sin30\cos30$$Algebra to the rescue! $$\cos 30 = \sin 60 =2\sin 30 \cos 30$$
Ha! I thought that the sum-angle formula would do it, but then I saw your post and realized that it may not be simple. I'll take your word for it. :-)Prove it!
Well, they are all the same.I tried to plot the graphs of $$\cos 30, \sin 60, 2\sin 30 \cos 30$$ $$\cos30$$ is not same as $$\sin60$$ and $$2\sin30\cos30$$
Once you get the sine and cosine for 30 degrees ( e.g. from the double angle formula), then you can return to the geometric approach to get them for 15 and 75 degrees.Ha! I thought that the sum-angle formula would do it, but then I saw your post and realized that it may not be simple. I'll take your word for it. :-)
Plotting graphs doesn't make any sense, because all of these expressions just represent numbers. Furthermore, the various trig identities show that ##\cos(30°)## is exactly equal to ##\sin(60°)##, and the double angle formula (also an identity) shows that ##\sin(60°) = \sin(2 * 30°) = 2\sin(30°)\cos(30°)##. Also, if you're using a calculator, make sure it's in degree mode, not radian mode.I tried to plot the graphs of ##\cos 30, \sin 60, 2\sin 30 \cos 30## ##\cos30## is not same as ##\sin60## and ##2\sin30\cos30##
All I am trying to understand is if there is a right-angled triangle 30 - 60 - 90, why adjacent side is given 1√3 unit, its hypotenuse 2 units and its opposite side is 1 unit? Where did they come from?
Yes, you are obsessed with plotting graphs, all your questions are about plotting graphs but you cannot learn anything this way.Plotting graphs doesn't make any sense, because all of these expressions just represent numbers.
The problem started with why are those particular side lengths are determined by the 30 degree and 60 degree angles. So Pythagoras is not enough.If you don't understand why the base of that triangle is ##\sqrt{3} ## long then you are not ready for sine and cosine yet, you need to start with Pythagoras.
But it continued withThe problem started with why are those particular side lengths are determined by the 30 degree and 60 degree angles.
So while Pythagoras may not be sufficient he is necessary.In a right-angled triangle ... Where did the side lengths 1, 1√3, 2 come from?
I would get the two side lengths using trigonometry, not using the Pythagorian Theorem at all (although it could be used to get the third side).But it continued with
So while Pythagoras may not be sufficient he is necessary.
How did I not see that?Take an equilateral triangle of side 2. Cut it in half along a bisector.
As I wrote in post #19, just before @pasmith's post, the problem can be done without invoking trig -- just with a bit of geometry and Pythagorus. Equilateral triangles are studied in geometry, along with the facts that all three sides and angles are equal -- at least they were when I had geometry in the last century.I would get the two side lengths using trigonometry, not using the Pythagorian Theorem at all (although it could be used to get the third side).
For cos of 1 deg, use power series expansion ##cos(x) \approx 1-\frac{x^2}{2}## where ##x=\frac{\pi}{180}##.Summary:: How do I know that cosine of 1 degree is: 0.9998
Why is cos (1)° = 0.9998?
cos(60)° = ½?
Thanks.
At 1 degree, the small angle approximation ##\sin {x} \approx x ## makes the estimate ##\cos {x} \approx \sqrt {1-x^2}## accurate to 7 digits.For cos of 1 deg, use power series expansion ##cos(x) \approx 1-\frac{x^2}{2}## where ##x=\frac{\pi}{180}##.
That for 1 degree, just draw the figure and your guess should be about what you have there. For the 60 degree, this is already obvious through fairly simple Geometry.Summary:: How do I know that cosine of 1 degree is: 0.9998
Why is cos (1)° = 0.9998?
cos(60)° = ½?
Thanks.
So this points back to some of the simpler Geometry you study in high school, about right triangles, some regular polygons, equilateral triangles.Yes, you are obsessed with plotting graphs, all your questions are about plotting graphs but you cannot learn anything this way.
If you don't understand why the base of that triangle is ##\sqrt{3} ## long then you are not ready for sine and cosine yet, you need to start with Pythagoras. This course should do:
https://www.khanacademy.org/math/geometry/hs-geo-trig
I think you really meant "sides o three"? Two of the sides become hypotenuses of the two new triangles after bisecting the equilat. into the two right triangles.Take an equilateral triangle of side 2. Cut it in half along a bisector.
Take an equilateral triangle of side 2. Cut it in half along a bisector.
No, @pasmith meant what he wrote; namely, an equilateral triangle whose sides are of length 2.I think you really meant "sides o three"? Two of the sides become hypotenuses of the two new triangles after bisecting the equilat. into the two right triangles.
Pytagoras's theoremIn a right-angled triangle 30 - 60 - 90, why adjacent side is given 1√3 unit, its hypotenuse 2 units and its opposite side is 1 unit?
If you have got understood the formulaWhy is cos (1)° = 0.9998?