Could someone explain this solution please?

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The discussion focuses on understanding the derivation of the probability, P(N), in a statistical mechanics context. The probability is expressed as P(N) = p^N * q^(N0-N), where p = V/V0 represents the likelihood of a single molecule being in a specific volume V, and q = 1 - p is the probability of it being outside that volume. The total probability accounts for the combinatorial selection of N particles from a total of N0, calculated using the binomial coefficient \binom{N_0}{N} = N_0! / (N! * (N0-N)!). This foundational understanding is crucial for grasping basic probability in statistical mechanics.

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We got this in class from a TA and the professor is in China and not able to answer questions. I am confused by where the probability,P(N), comes from in part a. It looks like a multiplicity multiplied by some other stuff but I don't understand it at all. I haven't had any probability/statistics but I assume it's pretty basic. If anyone could help me understand how this probability comes about it would be much appreciated. Thanks
 
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p=V/V0 is the probability that one molecule be in the volume V. q=1-p is the probability that it be somwhere else. This expression of q comes from the fact that since the particle must be somewhere we must have p+q=1.

Choose N particles among N0. The probability that these N be in V and that the rest of them are NOT in V is p^Nq^{N_0-N}. In general, the probability that exactly N particles be in V and the rest not in V is p^Nq^{N_0-N} summed over as many ways there are to choose which N particles among N0 are going to be in V. And you probably at least know some basic probability results, among which that the number of ways to chose N amongst N0 is \binom{N_0}{N}=\frac{N_0!}{N!(N_0-N)!}

So we have the result.
 
Thanks, that makes it much clearer.
 

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