Could someone please explain to me the integral used to compute work done?

AI Thread Summary
The integral used to compute work done is expressed as the integral from a to b of F * dl, where F is the force vector and dl is a differential length along the path. The limits a and b represent the starting and ending points of the path, not moments in time. Dl is not simply l2-l1; it represents an infinitesimally small segment of the path. Understanding that integration involves multiplication of changing factors is crucial, especially when dealing with vectors that require consideration of direction. For practical understanding, sample problems and detailed explanations are available on educational websites.
WahooMan
Messages
22
Reaction score
0
I know the integral to compute work done is

(integral from a to b) F * dl

where F and l are vectors, but I don't understand how I would use that in a problem.

1. Are a and b moments in time?

2. What is dl? Is that the same thing as l2-l1? So would it be (integral from a to b) F(l2-l1) and just integrate that?

Any help would be greatly appreciated. Thanks.

Edit: It would really be helpful if someone could provide a sample problem and explain how to do it that way.
 
Last edited:
Physics news on Phys.org
Just remember that integration is MULTIPLICATION when one
of the factors is changing.
Since multiplication is nothing more than repeated addition,
you can see the reason for the S sigma as the symbol for integration.

With vectors it is a little more involved since directions are also must be considered
That is all
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top