Coulomb's Law and Metallic Sheets: Impact on Force Between Charges

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In summary, when two equal and opposite charges are placed at a distance r from each other and a large metallic sheet is placed at a distance d from them, the attractive force between the charges along the direction joining them decreases if image charges are placed at a distance d to the left of the metallic plate. This is due to the repulsive forces between the image charges, which act opposite to the attractive force between the real charges.
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niranjan_learner
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Homework Statement


Two equal and opposite charges are placed at a distance r from each other. A large metallic sheet is placed at a distance d from them as shown in the figure. Due to the presence of the sheet, the attractive force between the charges along the direction joining them:
[Please Note: Figure attached]

1. decreases
2. increases
3. remains unchanged
4. decreases if r > d/2 and increases if r < d/2

Homework Equations


Coulombs equation for force between two charges.

The Attempt at a Solution



I attempted the problem by placing image charges -q and +q at a distance d to the left of the metallic plate. In that case the force between the real charges along the line joining them decreases. Is this solution acceptable?

Please review my answer. Thank you!
 

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  • #2
niranjan_learner said:
In that case the force between the real charges along the line joining them decreases. Is this solution acceptable?
Can you provide your reasoning why you think so?
 
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  • #3
kuruman said:
Can you provide your reasoning why you think so?

Thank you Kuruman for replying.

My reasoning is as follows:

Lets place the image charges on the left side of the metallic plate. Now the two image charges and the two real charges occupy corners of a rectangle with length 2d and width r with like charges on the diagonally opposite corners. There exists repulsive forces between these like charges. The direction these repulsive forces is along the lines joining them; i. e along the diagonals. The components of these forces along the line joining real charges acts opposite to the attractive force between them. So the force between the real charges along the line joining them decreases.

Please provide your comment on this.
 
  • #4
No comment needed. Your reasoning is correct.
 
  • #5
kuruman said:
No comment needed. Your reasoning is correct.
Thank you Kuruman. :)
 

1. What is Coulomb's law?

Coulomb's law is a fundamental law in physics that describes the force between two charged particles. It states that the force of attraction or repulsion between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

2. How do I calculate the force using Coulomb's law?

The force between two charged particles can be calculated using the formula F = k(q1q2)/r^2, where F is the force in Newtons, k is a constant equal to 8.99 x 10^9 Nm^2/C^2, q1 and q2 are the charges of the particles in Coulombs, and r is the distance between the particles in meters.

3. Can Coulomb's law be applied to point charges only?

No, Coulomb's law can be applied to any two charged objects, regardless of their size or shape. However, it is most accurate for point charges, which are objects with a very small size compared to the distance between them.

4. What is the direction of the force in Coulomb's law?

The force between two charged particles is a vector quantity, meaning it has both magnitude and direction. The direction of the force is along the line connecting the two particles, and it can be either attractive or repulsive depending on the charges of the particles.

5. How does the distance between two charged particles affect the force?

According to Coulomb's law, the force between two charged particles is inversely proportional to the square of the distance between them. This means that as the distance between the particles increases, the force decreases and vice versa. This is known as an inverse square relationship.

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