Couple moment problems - Calculate the distance?

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The discussion revolves around calculating the distance in a couple moment problem using the equation M = F x d. The participant calculates the distance x as 0.57m by rearranging the moment equation, resulting in a moment of 20Nm with a force of 35N. They further determine the total distance d by applying the cosine of 30 degrees, yielding a final distance of 0.66m. Another participant confirms the calculations are correct, suggesting a different variable could enhance clarity. The solution effectively demonstrates the application of moment equations in physics.
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Couple moment problems -- Calculate the distance?

Homework Statement




http://imageshack.com/a/img691/1734/804i.jpg


Homework Equations



M = F x d

The Attempt at a Solution



M = Fxd
20Nm = 35N*x
x = 0.57m

cos 30 deg = x/d
d = x/cos 30 deg = 0.57m/cos 30 deg = 0.66m

is this correct?
 
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nchin said:

Homework Statement




http://imageshack.com/a/img691/1734/804i.jpg


Homework Equations



M = F x d

The Attempt at a Solution



M = Fxd
20Nm = 35N*x
x = 0.57m

cos 30 deg = x/d
d = x/cos 30 deg = 0.57m/cos 30 deg = 0.66m

is this correct?
Yes, I think that is correct. (I might have used a different variable besides 'x', so as not to confuse it with the x-axis direction specified in the diagram, but the final answer works out the same).
 
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