Couple More Questions on Electrostatics

AI Thread Summary
Electrostatic attraction between two objects indicates that one is positively charged and the other negatively charged. The force of gravity acting on a positively charged plastic sphere of 4.8E-19 C in a gravitational field of 9.8 m/s² is calculated to be 5.8E-14 N. Benjamin Franklin defined a negative charge as an excess of electrons compared to protons. The electric field strength at a point 3.0 cm from a 5.0 µC charge is determined to be 5.0E7 N/C, with field lines originating from positive charges. The discussion also explores variations in electric field diagrams for different charge configurations, such as dipoles and charges within external fields.
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Homework Statement


1) From the observation that there's an electrostatic attraction between object A and B, what's the most you can conclude about the electric charge on A and B?

2) A plastic sphere with a positive charge of 4.8E-19 C is held stationary in a gravitational field of strength 9.8m/s/s by an electric field of strength 1.2E5 N/C. What is the force of gravity of the sphere?

3)How did Benjamin Franklin define a negative charge?

4) Draw a diagram to show the lines of force around a small positive charge.

5) Point P is 3.0 cm away from a small object with a positive charge of magnitude 5.0 muC. What is the electric field strength at point P?

Homework Equations


F=QE
F=kQq/d^2


The Attempt at a Solution


1) One has to be positive and one has to be negative.

2) 1.2E5 N/C=Fg/4.8E-14 N
Fg=5.8E-14 N

3) He defined it as having more electrons than protons.

4)
positive.jpg


5) QE=(kQq)/r^2
E=(kq)/r^2
E=[(9.0E9)(5.0E-6 C)]/(0.030m)^2
E= 5.0E7 N/C
 
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In the diagram, remember that the lines of the electric field (and hence the lines of force) originate on + charges and terminate on - charges. How would that change your drawing some?
 
you mean drawing the lines out of the positive charge?
 
Fusilli_Jerry89 said:
you mean drawing the lines out of the positive charge?

Maybe...

There would be two cases, with variations on those two cases, right? The first would be a simple diplole, where there are two equal charges spaced apart. What would the E field distribution (and therefore the force vector field) look like for that?

The second case is a positive charge embedded in an overall E field that is generated by something external (like a positive ion sitting between the plates of a capacitor). How would that change the E field diagram?
 
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