Covariance in Equations: How to Identify and Understand It

  • Thread starter Thread starter tiger_striped_cat
  • Start date Start date
  • Tags Tags
    Covariant
AI Thread Summary
To determine if an equation is covariant, it must meet two criteria: all quantities must have the same type of indices summed over, ensuring the tensor ranks on both sides are equal, and both sides must have the same tensor quality, meaning they cannot equate a tensor with a non-tensor. The example provided, A^{i}=F^{\mu i}B_{\mu}, is deemed non-covariant because one index has four values while the other has three, indicating an imbalance. Additionally, the transformation behavior of the indices differs, as one index uses a 4x4 transformation matrix while the other uses a 3x3 matrix. Understanding these principles is crucial for recognizing covariance in equations.
tiger_striped_cat
Messages
49
Reaction score
1
How can you tell if an equation is covariant just by looking at it. Please try and keep explaniation to text more than equations.
 
Physics news on Phys.org
tiger_striped_cat said:
How can you tell if an equation is covariant just by looking at it. Please try and keep explaniation to text more than equations.

There are basically two criteria:
1.The equation must contain only quantities with the same type of greek/spacetime indices summed over.Wrt to indices,the equation must be 'balanced',that is the tensor rank of the RHS must be equal to the tensor rank of the LHS.
2.The sides of the equation must have the same 'tensor quality' (i made it up).You cannot have an equality between a tensor (e.g.in the LHS) and a nontensor (in the LHS).

Daniel.

PS.The equation
A^{i}=F^{\mu i}B_{\mu}
is not covariant.
 
Thank you for your great explaniation. But could you explain the example:

A^{i}=F^{\mu i}B_{\mu}


I think I'm having problems due to my lack of understanding with tensors and covariance, no fault of your explaniation.
 
It's basically the "F" 'animal'.The way it's given,it's not a tensor because:
a) one index takes 4 values and the other only 3.
b) both indices should behave the same at a general coordinate transformation,but the trouble is that one index transforms with the normal matrix (4*4),while the other with another one,which has only (3*3) components.

Daniel.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top