Crate sliding on a flatbed truck

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The discussion revolves around a crate of oranges on a flatbed truck, focusing on the forces of friction acting on the crate under different conditions. For part (a), the force of friction is determined to be zero since the truck is moving at a constant speed, resulting in no acceleration. In part (b), when the truck accelerates at 1.0 m/s², the static frictional force calculated is 54N, which is less than the force required to keep the crate stationary, indicating it will slide. For part (c), the maximum acceleration without sliding is calculated to be 2.94 m/s², based on the static friction limit. Overall, the calculations confirm the crate's behavior under varying truck speeds and accelerations.
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A crate of oranges weighing 180N rests on a flatbet truck 2.0m from the back of the truck. The coefficients of friction between the crate and the bed are us=0.30 and uk=0.20. The truck drives on a straight, level highway at a constant 8.0 m/s. (a) What is the force of friction acting on the crate?
(b) If the truck speeds up with an acceleration of 1.0 m/s^2, what is the force of friction on the crate?
(C) What is the maximum acceleration the truck can have without the crate starting to slide?

Please help asap!
 
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F=MA

\sum F = \vec F_{fric} + \vec F_{car} [/tex]
 
I still don't understand You can't use that equation for all three answers can you?
 
Actually, he shouldn't be telling you much of anything, since you haven't shown how you started the problem and where you got stuck. :-p

Rather than tell you how to do it, I am going to ask you some questions to get you going in the right direction.

lilkrazyrae said:
(a) What is the force of friction acting on the crate?

Have you drawn a free body diagram of the crate?
What is the crate's acceleration?
What must the net force be equal to?

(b) If the truck speeds up with an acceleration of 1.0 m/s^2, what is the force of friction on the crate?

Again: Have you drawn a free body diagram?
Given the acceleration, what must the net force be equal to?
What is the maximum static frictional force?
Is that frictional force exceeded here?

(C) What is the maximum acceleration the truck can have without the crate starting to slide?

If you can get (b) then you should be able to get this.

Give it a shot and let us know what you come up with.
 
Alright I used your questions and I got answers for all the parts but now the question is did I use your suggestions correctly. So could you tell me if I did this stuff right. On (a) I got the acceleration to be zero therefore the net force is zero. (b) F static friction equals 54N. (c) I get 54N = 180/9.8 *a which equals 2.94 m/s^2 for the max acceleration Let me know how I did please!
 
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