Creating a berm with a 1:1 slope

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Discussion Overview

The discussion revolves around a homework problem involving the construction of a berm using soil and hay bales, specifically focusing on how to calculate the height of the hay bale walls needed to accommodate a specified volume of soil while considering a 1:1 slope for the fill. The problem includes calculations related to volume and geometry.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant calculates the height required for 324,000 cubic feet of soil in a rectangular area and finds it to be 40.5 feet without considering the slope.
  • Another participant points out a typo in the volume, correcting it to 32,400 cubic feet, which affects the calculations.
  • Participants express uncertainty about how to account for the 1:1 slope and how it impacts the height of the walls and the volume of soil extending above the walls.
  • There is a suggestion that the shape of the berm, when sloped, may resemble a pyramid, which could influence the calculations.
  • One participant notes that the problem might be simpler if the base were square instead of rectangular.

Areas of Agreement / Disagreement

Participants generally agree on the need to consider the slope in their calculations, but there is no consensus on how to proceed with the calculations or the implications of the shape of the berm.

Contextual Notes

Participants have not resolved how to calculate the volume of soil extending above the walls or how the slope affects the overall height needed for the hay bales. There are also unresolved assumptions regarding the geometry of the berm.

thatboygood
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Homework Statement



324,000 cubic feet of soil is to be placed in a rectangular area (constructed from hay bales) of 80 feet x 100 feet. Using a slope of 1:1 for the fill soil, how many bales high must the walls be stacked to accommodate the soil?
Assume the hay bales have a height of 18"



Homework Equations


A = L x W
V = A x h

Volume of a pyramid...? 1/3(L x W x h) = V


The Attempt at a Solution



I started by calculating the required height (assuming the soil was filled without a slope):

324,000 cu ft = 8000ft x h
h = 40.5 ft

I know from here I would simply divide the total height (h) by the height of a hay bale (18"), to get the number of bails. However, I am thinking that my calculated height is too much, since the soil will be slopped (1:1 slop) and extend above the walls. My question is, how do I figure out how high the soil can be slopped above the walls? and what the volume of soil extending above the walls would be. I was thinking this may have something to do with calculating the volume of a pyramid... but I'm a bit confused as to how to proceed. Any help or suggestions would be greatly appreciated.
 
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thatboygood said:

Homework Statement



32,400 cubic feet of soil is to be placed in a rectangular area (constructed from hay bales) of 80 feet x 100 feet. Using a slope of 1:1 for the fill soil, how many bales high must the walls be stacked to accommodate the soil?
Assume the hay bales have a height of 18"



Homework Equations


A = L x W
V = A x h

Volume of a pyramid...? 1/3(L x W x h) = V


The Attempt at a Solution



I started by calculating the required height (assuming the soil was filled without a slope):

324,000 cu ft = 8000ft x h
h = 40.5 ft
The problem says 32,400 cu ft.
thatboygood said:
I know from here I would simply divide the total height (h) by the height of a hay bale (18"), to get the number of bails. However, I am thinking that my calculated height is too much, since the soil will be slopped (1:1 slop) and extend above the walls. My question is, how do I figure out how high the soil can be slopped above the walls? and what the volume of soil extending above the walls would be. I was thinking this may have something to do with calculating the volume of a pyramid... but I'm a bit confused as to how to proceed. Any help or suggestions would be greatly appreciated.
 
Mark44 said:
The problem says 32,400 cu ft.

That was a typo. Thanks for pointing it out. I have corrected it in my original post.
 
Do you have an idea of how the berm will look, with its sloped (not slopped) sides?
 
Mark44 said:
Do you have an idea of how the berm will look, with its sloped (not slopped) sides?

When sloped, it should resemble a pyramid.
 
OK.
The problem would be a bit easier if the base happened to be square, rather than rectangular.
 

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