Creating a berm with a 1:1 slope

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To create a berm with a 1:1 slope using 32,400 cubic feet of soil in an 80 feet by 100 feet rectangular area, the initial calculation for height without considering the slope results in 4.05 feet. However, the slope will extend the soil above the walls, complicating the height calculation. The discussion highlights the need to determine how high the soil can be sloped above the walls and the volume of soil extending above them. A pyramid volume calculation may be relevant for understanding the sloped structure. The conversation also notes that a square base would simplify the problem.
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Homework Statement



324,000 cubic feet of soil is to be placed in a rectangular area (constructed from hay bales) of 80 feet x 100 feet. Using a slope of 1:1 for the fill soil, how many bales high must the walls be stacked to accommodate the soil?
Assume the hay bales have a height of 18"



Homework Equations


A = L x W
V = A x h

Volume of a pyramid...? 1/3(L x W x h) = V


The Attempt at a Solution



I started by calculating the required height (assuming the soil was filled without a slope):

324,000 cu ft = 8000ft x h
h = 40.5 ft

I know from here I would simply divide the total height (h) by the height of a hay bale (18"), to get the number of bails. However, I am thinking that my calculated height is too much, since the soil will be slopped (1:1 slop) and extend above the walls. My question is, how do I figure out how high the soil can be slopped above the walls? and what the volume of soil extending above the walls would be. I was thinking this may have something to do with calculating the volume of a pyramid... but I'm a bit confused as to how to proceed. Any help or suggestions would be greatly appreciated.
 
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thatboygood said:

Homework Statement



32,400 cubic feet of soil is to be placed in a rectangular area (constructed from hay bales) of 80 feet x 100 feet. Using a slope of 1:1 for the fill soil, how many bales high must the walls be stacked to accommodate the soil?
Assume the hay bales have a height of 18"



Homework Equations


A = L x W
V = A x h

Volume of a pyramid...? 1/3(L x W x h) = V


The Attempt at a Solution



I started by calculating the required height (assuming the soil was filled without a slope):

324,000 cu ft = 8000ft x h
h = 40.5 ft
The problem says 32,400 cu ft.
thatboygood said:
I know from here I would simply divide the total height (h) by the height of a hay bale (18"), to get the number of bails. However, I am thinking that my calculated height is too much, since the soil will be slopped (1:1 slop) and extend above the walls. My question is, how do I figure out how high the soil can be slopped above the walls? and what the volume of soil extending above the walls would be. I was thinking this may have something to do with calculating the volume of a pyramid... but I'm a bit confused as to how to proceed. Any help or suggestions would be greatly appreciated.
 
Mark44 said:
The problem says 32,400 cu ft.

That was a typo. Thanks for pointing it out. I have corrected it in my original post.
 
Do you have an idea of how the berm will look, with its sloped (not slopped) sides?
 
Mark44 said:
Do you have an idea of how the berm will look, with its sloped (not slopped) sides?

When sloped, it should resemble a pyramid.
 
OK.
The problem would be a bit easier if the base happened to be square, rather than rectangular.
 

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