Cumulative distribution and density functions

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SUMMARY

The discussion focuses on finding the cumulative distribution function (CDF) for a random variable X with a given probability density function (PDF) defined as 0.048(5x - x²) for 0 < x < 5 and 0 otherwise. The CDF is established as F(x) = 0 for x ≤ 0, F(x) = ∫(0 to z) (0.048(5x - x²)) dx for 0 < z < 5, and F(x) = 1 for x ≥ 5. Participants emphasize the importance of integrating the PDF correctly to derive the CDF and suggest reviewing course materials for similar examples.

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EngnrMatt
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Homework Statement



Let X be a random variable with probability density function:

0.048(5x-x2) IF 0 < x < 5

0 otherwise

Find the cumulative distribution function of X

a) If x ≤ 0, then F(x) =

b) If 0 < x < 5, then F(x) =

c) If x ≥ 5, then F(x) =

Homework Equations



Not quite sure

The Attempt at a Solution



The answer to a) is 0. The answer to c) is 1.

I am making the reasonable assumption that a) is 0 because there is no probability at that point, and that c) is 1 because after that, all probability has been "used" so to speak. However, integrating the function between 0 and 5 does not work. It seems as if my professor totally skipped over teaching us this particular type of problem. Statistics usually makes a good deal of sense to me, but this is pretty foreign.
 
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EngnrMatt said:

Homework Statement



Let X be a random variable with probability density function:

0.048(5x-x2) IF 0 < x < 5

0 otherwise

Find the cumulative distribution function of X

a) If x ≤ 0, then F(x) =

b) If 0 < x < 5, then F(x) =

c) If x ≥ 5, then F(x) =

Homework Equations



Not quite sure

The Attempt at a Solution



The answer to a) is 0. The answer to c) is 1.

I am making the reasonable assumption that a) is 0 because there is no probability at that point, and that c) is 1 because after that, all probability has been "used" so to speak. However, integrating the function between 0 and 5 does not work. It seems as if my professor totally skipped over teaching us this particular type of problem. Statistics usually makes a good deal of sense to me, but this is pretty foreign.

You say "integrating the function between 0 and 5 does not work". What about it does not work?

In fact, if we define f(x) = 0 for x < 0 and for x > 5, then the cumulative distribution F(z) is
F(z) = \int_{-\infty}^z f(x) \, dx \\<br /> = 0 \; \text{ if } z &lt; 0,\\<br /> = \int_0^z (48/1000)(5x - x^2) \, dx \; \text{ if } 0 \leq z \leq 5,\\<br /> = 1 \; \text{ if } z &gt; 5.
Do the integration to see what you get.

Are you sure your course notes or textbook do not have any similar examples?
 

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