Current density in graphene-giant?

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SUMMARY

The current density in graphene is calculated using the formula J=q*n*v, where q is the elementary charge, n is the electron density (6*10^12 cm^-2), and v is the Fermi velocity (10^8 cm/s). This results in a current density of 100 A/cm, which is considered a realistic and significant value for graphene. Understanding this calculation is essential for projects involving graphene, as it highlights the material's exceptional electrical properties.

PREREQUISITES
  • Understanding of current density calculations in physics
  • Familiarity with graphene's electronic properties
  • Knowledge of Fermi velocity and its implications
  • Basic concepts of electron density in materials
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  • Research the implications of high current density in graphene applications
  • Explore advanced topics in graphene's electronic properties
  • Learn about the methods for measuring electron density in materials
  • Investigate the role of Fermi velocity in semiconductor physics
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Researchers, materials scientists, and engineers working on graphene applications, particularly in electronics and nanotechnology, will benefit from this discussion.

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Hi,

I just read a paper on graphene's basic properties and it says that since current density J is given as

J=q*n*v

where q is the elementary charge, n is the electron density and v is the Fermi velocity of electrons and for graphene n=6*10^12 cm^-2 and v=10^8 cm/s, the current density in graphene is giant as J=100A/cm. It doesn't sound right. Is it a realistic value for J? Or what can I do to correctly interpret this?

Thanks.
 
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I'm sorry you are not generating any responses at the moment. Is there any additional information you can share with us? Any new findings?
 
Bumping this because I'm interested in the answer too. (Will be starting a project with graphene soon)

Also, if anyone replies - is there an intuition behind graphene's basic properties? Right now I'm not really getting why graphene is the way it is.
 

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