Current Electricity - current flowing through hand

AI Thread Summary
The discussion revolves around calculating the resistance of dry skin and the current flowing through a person who accidentally grabs a wire at 50V. For a 1mm thick layer of dry skin, the resistance is determined to be 3.0 x 10^5 ohms. The calculation for the current flowing through the person, initially miscalculated, is clarified with the correct approach leading to an estimated current of 1.89 mA. Participants discuss the effect of contact area on resistance and confirm that while potential may vary slightly along the wire, it does not significantly affect the calculations. The conversation emphasizes understanding resistance and current flow in electrical safety scenarios.
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Current Electricity -- current flowing through hand

Homework Statement



i)For a layer dry skin 1mm thick, determine the resistance of a 1 cm^2 area of skin.
Resistivity of dry skin : 3 x 10^4 ohms m

[3.0 x 10^5 ohms ]
ii)A person, who is well-earthed, accidentally grabs a wire of diameter 0.4 cm at a potential of 50V. His hand makes contact with the whole circumference of the wire over a distance of 9cm.
The average thickness of skin of his hand is 1mm. Estimate the current flowing through him.

[1.89 mA ]

Homework Equations



Resistance = resistivity(length)/area
V = IR

The Attempt at a Solution



For i) , I managed to solve it.
Using the equation directly.

For ii), I couldn't get the answer.

First, I calculate the surface area of the cylinder ( wire ) where it is in contact with the wire.

Surface area = pi . diameter . length
= pi . (0.4 x 10^-2) . (9 x 10^-2)
= 0.0011309 m^2
Then I multiply this surface area with the resistance of dry hand obtain in i)

Total resistance = surface area x resistance of dry skin 1 mm thick, area of 1m^2
= 0.0011309 x 3.0 x 10^5

Next, I used V = IR. Sub in total resistance and P.D of 50 V
The answer I got was 0.147 A. Totally off.

Thanks for the time !
 
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hi sharkey1314! :smile:
sharkey1314 said:
Then I multiply this surface area with the resistance of dry hand obtain in i)

but won't the resistance go down if the area of contact increases? :wink:
 


Thanks a lot. I re-used the equation for resistance to find the new resistance of the hand. Then, after using V = IR, I managed to get the answer =D

Just to clarify, what does a potential of 50V means ? And does the potential changes along the length of the wire. i.e. the start and end point will have different potential ? If so, does the answer change since potential varies.
 
sharkey1314 said:
Just to clarify, what does a potential of 50V means ?

it means the potential difference between the wire and the ground …

ie from your hand to your foot! :biggrin:
And does the potential changes along the length of the wire. i.e. the start and end point will have different potential ? If so, does the answer change since potential varies.

Yes, but only very slightly …

the drop in potential along a wire is IR, and R for a wire is usually very small! :smile:
 
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