Current from 2.2 Micro F Capacitor

AI Thread Summary
The discussion centers on calculating the maximum current delivered by a 2.2 Micro F capacitor connected to a North American outlet with 110V and 60Hz. The initial calculation used the formula I = Vmax / XC, but the participant miscalculated the reactance (XC) as 8.29 ohms instead of the correct value of 1.2 kOhm. Consequently, the maximum current (Imax) was incorrectly calculated as 13.29 A instead of the accurate 91.2 mA. The correction highlights the importance of precise calculations in electrical engineering contexts. Accurate calculations are crucial for understanding capacitor behavior in AC circuits.
cseet
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Hi all,
can somebody please advise whether the below answer is correct... or am I on the right path??

Q: What maximum current is delivered by a 2.2 Micro F capacitor when connected to a North American Outlet where Vrms = 110V and f = 60 hz?

my answer:
I = Vmax / XC

XC = 1 / wC
= 1 / 2 pie 60 * (2.2 * 10E-6)
= 8.29 ohm

I = Vmax / XC
= 110 / 8.29
= 13.29 A

Please kindly correct me if I was wrong...
thanks
Cseet
 
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You are correct, except for the calculation of Xc. The formula is correct, but you miscalculated it. Xc should be 1.2kohm, and Imax should be 91.2mA.
 
Hi Chen,
thanks alot, you're a GEM!
cseet
 

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