Calculating Current in DC Motor at 11V, 2000 RPM

AI Thread Summary
To calculate the current drawn by a 12V permanent magnet DC motor operating at 11V and 2000 RPM, the stall current is given as 2 amperes, allowing the resistance to be determined as 6 ohms. The back electromotive force (e.m.f) is proportional to the motor's speed, which can be expressed in relation to the maximum speed and voltage. By applying the relationship between speed, voltage, and current, the current at the specified conditions can be calculated. The resistance value is crucial for determining the current since it influences the back e.m.f. Thus, the current can be accurately calculated using the derived resistance and the motor's operational parameters.
farry1024
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Question:
Assume that a 12V permanent magnet DC motor is to be used for moving the robot legs.
It has a stall current of 2 ampere and a no load speed of 3000 r.p.m.
Assumer that the friction at no load spped was so little that it can be neglected .
When the suply is at 11V, the motor is moving the legs at its rated speed of 2000 rom due to firction, what current would it draw?

I try to answer:
Vmax = 12V
Imax = 12A
ωmax = 3000 rpm <<<ω=omoega, i.e. rotational speed

V1 = 11V
I1 = unknown
ω1 = 2000 rpm

back e.m.f proportional to ω

ω1/ ωmax = back e.m.f 1 / back e.m.f max
and back e.m.f = V- Ir

ω1/ ωmax = [ V1 - I1 ( r ) ] / [ Vmax - I max (r)]

However, I find that I do not have the resistance, how can I calculate? thanks.
 
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You know that the stall current is 2 amperes, and when the motor is stalled there is no back emf. So the resistance is 12 V/2 A = 6 ohms.
 
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