Current Ionic Solution, Charges

AI Thread Summary
The discussion revolves around calculating the current passing through a sodium chloride solution, with specific ion counts provided for Na+ and Cl- ions. The initial calculations yield a current of -1.984 mA, leading to confusion regarding the treatment of opposing charges. Participants clarify that while the ions move in opposite directions, their contributions to current should be considered based on their magnitudes rather than signs. A math error in the final summation is identified, emphasizing the need for careful consideration of charge directionality. Ultimately, the conversation highlights the importance of correctly interpreting current contributions from ions in an electrolytic solution.
PeachBanana
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Homework Statement



Current passes through a solution of sodium chloride. In 1.00 second, 2.68*10^16 Na+ ions arrive at the negative electrode and 3.92*10^16 Cl- ions arrive at the positive electrode. What is the current passing between the electrodes? Final answer must be in milliamperes.

Homework Equations



I = Q / Δt

The Attempt at a Solution



2.68*10^16 Na+ (1.6*10^-19 C) = 4.288 ma
3.68*10^16 Cl- (-1.6*10^-19C) = -6.272 ma

4.288 ma + (-6.272 ma) = -1.984 ma

Why is this incorrect?
 
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The ions aren't traveling in the same direction.
 
Bhumble said:
The ions aren't traveling in the same direction.

As far as I can tell OP accounted for that.

PeachBanana said:
3.68*10^16 Cl- (-1.6*10^-19C) = -6.272 ma

Buy a new calculator.
 
dQ/dt = I
opposite charges moving in opposite directions. Depending on the reference point both are either positive or negative.
Unless I'm missing something...
 
OP treats one current as positive, other as negative - that's equivalent.

And there is a simple math mistake in the final summation.
 
I don't see how that is equivalent since they are moving in opposite directions.
Say you have two charges one at point A and one at point B with one being positive and one being negative.
If they both move to opposite points then the magnitude dQ is 2. I don't see why this problem is different.
 
Sigh, you are right. Call it a senior moment.
 
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