What is the magnitude of the current in this ionic solution?

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SUMMARY

The magnitude of current in the ionic solution is calculated by considering the flow of both positive and negative ions. In this case, 3.93×1015 positive ions with a charge of +2e and 9.01×1015 negative ions with a charge of -e are involved. The correct formula for current (I) is I = Ch in Q / Ch in T, where the charge of the positive ions must be multiplied by two. The final calculation should reflect the total charge contributed by both types of ions.

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  • Understanding of ionic solutions and ion charge
  • Familiarity with the concept of electric current
  • Knowledge of basic algebra for calculations
  • Proficiency in using scientific notation
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  • Calculate the total current using the formula I = Ch in Q / Ch in T with the correct charge values
  • Explore the relationship between ion concentration and current in ionic solutions
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BuBbLeS01
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Current...please help!

Homework Statement



In an ionic solution, 3.93×10^15 positive ions with charge +2e pass to the right each second while 9.01×101^5 negative ions with charge -e pass to the left. What is the magnitude of current in the solution?

Homework Equations



I = Ch in Q / Ch in T

The Attempt at a Solution



So I did...
R = 1.6x10^-19 * 3.93x10^15 / 1
R = -1.6x10^-19 * 9.01x10^15 / 1
and then I added them...what am I doing wrong?
 
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BuBbLeS01 said:
3.93×10^15 positive ions with charge +2e pass
You forgot to multiply by two here.
 

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