Current of Electricity: electrons

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To determine how many electrons pass a point in a wire carrying a current of 2.0 A for 1.0 hour, the total charge (Q) is calculated using Q = I × t, where t is converted to seconds (3600 seconds). The number of electrons is then found by dividing the total charge by the charge of a single electron (approximately 1.602 x 10^-19 C). After correcting a calculation error regarding the time conversion, the correct answer is found to be 1.3 x 10^19 electrons. The final answer aligns with option C. This illustrates the importance of careful unit conversion in electrical calculations.
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Homework Statement


A wire carries a current of 2.0 A for 1.0 hour. How many electrons pass a point in the wire in this time?
A
1.2 x 10-15
B
7.2 x 103
C
1.3 x 1019
D
4.5 x 1022

Homework Equations


Q=I/t

The Attempt at a Solution


Q=2(60)=120
number of electrons= 120/1.60217733 × 10-19= but the answer isn't any of the options..ok i realized my super careless mistake (1hr=60s)
 
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(1hr=60s)

Is it correct?
 
Thread 'Correct statement about size of wire to produce larger extension'

Thread 'Correct statement about size of wire to produce larger extension'

The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...
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