Current of Electricity: electrons

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SUMMARY

The discussion focuses on calculating the number of electrons passing through a wire carrying a current of 2.0 A for 1 hour. The correct calculation involves using the formula Q = I × t, where Q is the charge, I is the current, and t is the time in seconds. After converting 1 hour to seconds (3600 seconds), the total charge is 7200 coulombs. Dividing this by the charge of a single electron (1.60217733 × 10-19 coulombs) yields approximately 4.5 × 1022 electrons, confirming option D as the correct answer.

PREREQUISITES
  • Understanding of electric current and charge
  • Familiarity with the formula Q = I × t
  • Knowledge of the charge of an electron (1.60217733 × 10-19 coulombs)
  • Basic unit conversion (seconds to hours)
NEXT STEPS
  • Study the relationship between current, charge, and time in electrical circuits
  • Learn about the properties of electrons and their role in electricity
  • Explore advanced concepts in electromagnetism
  • Practice problems involving charge calculations in various scenarios
USEFUL FOR

Students studying physics, particularly those focusing on electricity and magnetism, as well as educators looking for practical examples of current calculations.

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Homework Statement


A wire carries a current of 2.0 A for 1.0 hour. How many electrons pass a point in the wire in this time?
A
1.2 x 10-15
B
7.2 x 103
C
1.3 x 1019
D
4.5 x 1022

Homework Equations


Q=I/t

The Attempt at a Solution


Q=2(60)=120
number of electrons= 120/1.60217733 × 10-19= but the answer isn't any of the options..ok i realized my super careless mistake (1hr=60s)
 
Last edited:
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(1hr=60s)

Is it correct?
 

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