Current on a spring to withstand a weight.

AI Thread Summary
To determine the current needed for a spring to support a mass without deformation, the magnetic field inside a solenoid is calculated using B=μ0nIz. The magnetic energy of the solenoid is expressed as W=μ0N2I2πR2/(2l). The force from the mass is given by F=mg, and the required magnetic force is derived from the energy gradient, leading to F=μ0N2IπR2/(l). Equating the forces allows for the calculation of current, resulting in I=mgl/(μ0N2πR2). The discussion emphasizes the importance of correctly interpreting the notation and ensuring the derivative is taken with respect to length.
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Homework Statement


You have a spring of length l, radius R, with N loops and n loops per unit length. If you consider it a solenoid, what current do you need to apply to withstand a mass m hanging from it, without stretching or shrinking the spring.

Homework Equations


Magnetic field inside a solenoid: B0nIz
Magnetic energy: W=∫∫∫B2/(2μ0)dV

The Attempt at a Solution


I calculated the magnetic energy of a solenoid and I got:
W=μ0N2I2πR2/(2l)

The force applied by the mass is:
F=mg

So, the magnetic force that I need is:
F=∇W(length constant)=μ0N2IπR2/(l)

Both forces must be equal. I solve for I and I get:
I=mgl/(μ0N2πR2)

Do you thing it is right?
 
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The approach looks good, but I get confused by the notation with I, l and l.
The derivative has to be with respect to length.
 
mfb said:
The approach looks good, but I get confused by the notation with I, l and l.
The derivative has to be with respect to length.

So should I derivate with respect to length and then equal that derivative to mg?
 
Sure. You are interested in the total energy after a length change to see if this length change happens.
 
mfb said:
Sure. You are interested in the total energy after a length change to see if this length change happens.

And after equaling both quantities, I solve for I (current), right?
 
Sure.
 
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