Cushion seat angle : Radius of curvature

AI Thread Summary
The discussion revolves around solving a physics problem related to the angle of a cushion seat in a moving car, specifically focusing on the radius of curvature and forces acting on the seat. Participants suggest starting with a free body diagram (FBD) to analyze the forces, including gravitational and normal forces, and how they relate to acceleration. There is debate about the relevance of the car's speed and curvature, with some suggesting that additional accelerations must be considered due to the car's motion. Various attempts at calculations yield different angles, indicating confusion about the correct approach. The conversation emphasizes the importance of accurately incorporating all forces and accelerations to arrive at the correct angle.
cmcd
Messages
33
Reaction score
0
The problem is stated in the attachment.

I would include my attempt at the question if I got anywhere.
I'm really only looking for a hint as to how I set up the solution.

PS, I understand how to work out the angle if the car wasn't moving.

Thanks




Homework Statement


Homework Equations


The Attempt at a Solution

 

Attachments

Physics news on Phys.org
It's question 11 by the way
 
cmcd said:
The problem is stated in the attachment.

I would include my attempt at the question if I got anywhere.
I'm really only looking for a hint as to how I set up the solution.

PS, I understand how to work out the angle if the car wasn't moving.

Thanks




Homework Statement


Homework Equations


The Attempt at a Solution


Start with a free body diagram (FBD).
 
  • Like
Likes 1 person
Is the radius of curvature and the speed of the car of any relevance?
 
At first glance, I don't think so. Your FBD will include forces, which will sum and be related to the acceleration...
 
  • Like
Likes 1 person
So I don't think I did it correct. I got an answer of 10.873°.

I started off with the forces on the box being mgsinθ parallel down the plain and mgcosθ perpendicular into the plain.

I broke up m x 4 (... mass x acceleration) into two components, 4mcosθ acting parallel to and up the plain, and 4msinθ acting into the plain.

Angle for slip...

mgsinθ + (mgcosθ + masinθ) x μ = macosθ

(g+μa)sinθ = (a - μg)cosθ

θ = ArcTan [(a-μg)/(g+μa)]

θ = 10.87°
 
cmcd said:
So I don't think I did it correct. I got an answer of 10.873°.

I started off with the forces on the box being mgsinθ parallel down the plain and mgcosθ perpendicular into the plain.

I broke up m x 4 (... mass x acceleration) into two components, 4mcosθ acting parallel to and up the plain, and 4msinθ acting into the plain.

Angle for slip...

mgsinθ + (mgcosθ + masinθ) x μ = macosθ

(g+μa)sinθ = (a - μg)cosθ

θ = ArcTan [(a-μg)/(g+μa)]

θ = 10.87°

Could you attach your FBD? That would be a help in figuring this out...
 
  • Like
Likes 1 person
http://s1372.photobucket.com/user/cmcdona22/library/?sort=3&page=1

Thanks
 
cmcd said:
Is the radius of curvature and the speed of the car of any relevance?

berkeman said:
At first glance, I don't think so. Your FBD will include forces, which will sum and be related to the acceleration...

Sorry, maybe I confused you with my reply. The motion of the car on the curved surface adds an additional acceleration beyond just gravity. That term should also be added in.
 
  • Like
Likes 1 person
  • #10
Is that an additional tangential and normal acceleration?
 
  • #11
cmcd said:
Is that an additional tangential and normal acceleration?

The braking force would be tangential and the centripital force would be normal, right?
 
  • Like
Likes 1 person
  • #12
Hey Berkeman, does this look okay to you?
I followed it through and I got an answer of 3.8° which is isn't right, but I think the FBD looks okay.
Thanks,
cmcd
 

Attachments

  • 001.jpg
    001.jpg
    33.4 KB · Views: 433
Back
Top