Cycle Permutation: Composition of (12345)(12345)

  • Thread starter Thread starter KevinL
  • Start date Start date
  • Tags Tags
    Cycle Permutation
KevinL
Messages
37
Reaction score
0
I feel like I'm doing this correctly but my professor gave us an answer that is different from what I'm getting.

Composition of (12345)(12345)

Reading right to left I get (13524) but the answer he gives is (135)(24)

The odd thing is I'm getting the rest of these correct so I don't feel like I'm doing it wrong.
 
Physics news on Phys.org
actually scratch that, made an error will get back to you
 
so just to be clear on notation, as it can get tricky I read p=(123) as acting as follows
p(1)=2
p(2)=3
p(3)=1

so applying this to the 3 case gives
(123) 123
=231

and note
(123)=(231)=(312)

so applying this in your case
(12345) 12345
=23451
(12345) 23451
34512

so we have
12345
34512

which gives (13524), same as you

not applying (135)(24) gives
(135) 12345
=32541
(24) 32541
34521
which is not the same

sorry for the alignment, can't get it to work
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

Similar threads

Back
Top