Cylindrical coordinates of line through a point?

whig4life
Messages
14
Reaction score
0

Homework Statement



Use cylindrical coordinates to describe the line through the point (1,1,0) and parallel to the z-axis.

Homework Equations



How does one go about this? Even my course book was unclear about this. Any general overview about how to do such a question will be helpful.

The Attempt at a Solution



The z-axis is (0,0,1) while the cylindrical coordinates are (√2, ∏/4, z)

Now, is the solution in the form of and r = (√2, ∏/4, 0) + (0,0,1)t? Or am I completely lost? (haha)
 
Last edited:
Physics news on Phys.org
Draw a line r from the origin to the line x = 1 at some point y. Connect that point with a line r going to the origin.
What is r(y)? Or - hint - r2(y)?
Then, can you express θ in terms of y?
Finally you wind up with f(r) = (const.) + g(θ).

EDIT: oh dear, I assumed the line parallel to the y axis. Never mind ...
 
Last edited:
hi whig4life! :smile:
whig4life said:
The z-axis is (0,0,1)

sorry to be pernickety, but no, (0,0,1) is a point, isn't it? :wink:

while the cylindrical coordinates are (√2, ∏/4, z)

correct :smile:
Now, is the solution in the form of and r = (√2, ∏/4, 0) + (0,0,1)t? Or am I completely lost? (haha)

it depends whether you want a parametric equation or an ordinary one

the ordinary equation is r = √2, θ = ∏/4

(just as in cartesian coordinates it would be x = y = 1)

the parametric equation is not (r,θ,z) = (√2, ∏/4, 0) + (0,0,1)t

you can't add non-cartesian coordinates (try adding (1,0,0) to (1,∏,0) … do you get (2,∏,0) ?)

it's (r,θ,z) = (√2, ∏/4, …?… ) ?
 
I was told: The answer should probably be given in parametric form

r = something, theta = something, z = something

So, any ideas? I've exhausted all my resources trying to look for this maybe a better mind can see it more clearly.
 
Last edited:
hi whig4life! :smile:

(just got up :zzz:)

the parametric equation would be r = √2, θ = ∏/4, z = … ?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top