MHB Dave's Airport Adventure: Find m + n!

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Dave's airport adventure involves calculating the probability that he walks 400 feet or less to a new gate after his original gate is changed. The problem is set in an airport with twelve gates, each 100 feet apart. The total number of gate combinations is 12X11, leading to a brute force calculation that initially yielded an answer of 52. However, a more refined approach using a grid representation shows that there are 76 valid outcomes, resulting in a probability of 19/33. The final conclusion emphasizes the importance of accurate calculations in probability problems.
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Dave arrives at an airport which has twelve gates arranged in a straight
line with exactly 100 feet between adjacent gates. His departure gate is
assigned at random. After waiting at that gate, Dave is told the departure
gate has been changed to a different gate, again at random. Let the
probability that Dave walks 400 feet or less to the new gate be a fraction
m/n , where m and n are relatively prime positive integers. Find m + n .

I got the answer 52 but I am not that happy with my solution.
(I think I solved it using brute force because the problem was simple)
Can someone show me a better way?

Total choices are 12X11.
I listed all the gates and tried each one out.
4+5 +6 + 7 +8 + 8 +8 +8 +7 + 6 +5 +4 = 76

76/121 = 19/33

Thanks.
 
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The horizontal and the vertical axes represent the first and the second random gates, respectively. The surrounded area represents points (x, y) such that |x - y| ≤ 4. This so because |x - y| ≤ 4 ⇔ -4 ≤ x - y ≤ 4 ⇔ x - 4 ≤ y ≤ x + 4. You need to calculate the number of thick dots. The number of unmarked points on the grid is 2(7 + ... + 1) + 12 = 7 * 8 + 12 = 68, so there are indeed 12 * 12 - 68 = 76 thick dots. The only remark is that 19 / 33 = 76 / 132, not 76 / 121.
 

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