DE explaining simple RC circuit

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SUMMARY

The discussion centers on deriving the equation for the rate of change of voltage (dV/dt) in a simple RC circuit involving resistors R1, R2, and capacitor C, with a command voltage (Vcmd). The user presents the equations Itot = Ires + Icap and Itot = V/R2 + C * dV/dt, leading to the rearranged form C*dV/dt = (Vcmd-V)/R1 - V/R2. A key point raised is the behavior of dV/dt as R1 approaches zero and infinity, with confusion over the implications of these limits. A response clarifies that an ideal voltage source with zero output impedance cannot be combined with an ideal capacitor in this context, which leads to non-physical results.

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  • Familiarity with differential equations and their application in circuit analysis.
  • Knowledge of convolution in the context of signal processing.
  • Concept of ideal voltage sources and their limitations in circuit design.
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  • Study the behavior of RC circuits under various conditions, focusing on transient analysis.
  • Learn about convolution techniques in circuit analysis for non-linear systems.
  • Explore the implications of using ideal versus non-ideal voltage sources in circuit simulations.
  • Investigate numerical methods for approximating solutions to differential equations in electrical circuits.
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Electrical engineers, students studying circuit theory, and anyone interested in understanding the dynamics of RC circuits and their mathematical modeling.

bill.connelly
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I'm trying to wrap me head around what should be a very simple system, but I just can't manage it. I know there is no closed form for this problem (ignoring a voltage step like is shown in the diagram below, imagine it is a arbitrary voltage supply, or even more exactly, that R2 changes over time), and that to solve it I need to convolve equations (though I would hope I could do a pretty good numerical approximation too).

attachment.php?attachmentid=22234&stc=1&d=1259790891.gif


What I'm trying to do is get the equation for dV/dt in terms of Vcmd, R1, R2 and C

So I know
Itot = Ires + Icap
Itot = V/R2 + C * dV/dt

I also know V = Vcmd - Itot*R1
Itot = (Vcmd-V)/R1

Therefore

(Vcmd-V)/R1 = V/R2 + C * dV/dt
rearranging gives
C*dV/dt = (Vcmd-V)/R1 - V/R

I like that, because it means as R1 drops to zero, dV/dt approaches infinity (which is what I would expect, i.e. V should approach Vcmd instantly) BUT if R1 did drop to zero, and V = Vcmd, dV/dt should be zero, right? But that equation says otherwise. Likewise, as R1 approaches infinity, I would have thought dV/dt would approach zero.

Am I doing something wrong here? Making an invalid assumption?
 

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bill.connelly said:
I'm trying to wrap me head around what should be a very simple system, but I just can't manage it. I know there is no closed form for this problem (ignoring a voltage step like is shown in the diagram below, imagine it is a arbitrary voltage supply, or even more exactly, that R2 changes over time), and that to solve it I need to convolve equations (though I would hope I could do a pretty good numerical approximation too).

attachment.php?attachmentid=22234&stc=1&d=1259790891.gif


What I'm trying to do is get the equation for dV/dt in terms of Vcmd, R1, R2 and C

So I know
Itot = Ires + Icap
Itot = V/R2 + C * dV/dt

I also know V = Vcmd - Itot*R1
Itot = (Vcmd-V)/R1

Therefore

(Vcmd-V)/R1 = V/R2 + C * dV/dt
rearranging gives
C*dV/dt = (Vcmd-V)/R1 - V/R

I like that, because it means as R1 drops to zero, dV/dt approaches infinity (which is what I would expect, i.e. V should approach Vcmd instantly) BUT if R1 did drop to zero, and V = Vcmd, dV/dt should be zero, right? But that equation says otherwise. Likewise, as R1 approaches infinity, I would have thought dV/dt would approach zero.

Am I doing something wrong here? Making an invalid assumption?

Not sure why you think there is no closed form solution -- looks like your equations are just fine. The only issue is the infinity you think you are getting with R1 --> 0. You cannot use an ideal voltage source with zero output impedance and an ideal capacitor together in series with a voltage step. The non-real zero output impedance of the voltage source is what is giving you the non-real infinity.
 

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