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Homework Help: Dealing with an exponentially debilitating problem

  1. Mar 10, 2008 #1
    I can't resolve v(cubed)/exp(v)-1
    which is the RHS of an equation that has been sorted out of the left!
    I am rather hoping that this becomes v(cubed)/v which simplifies to v^2.

  2. jcsd
  3. Mar 10, 2008 #2


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    What are you trying to express, and what are you trying to find? Are you starting with this:

    [tex] \[
    \frac{{v^3 }}{{e^v }} - 1
  4. Mar 10, 2008 #3
    Sorry for the delay in responding!
    No it is the RHS of Planck's equation for B(v)T
    The LHS as I have reduced it to =Bc^2/2H
  5. Mar 10, 2008 #4
    Actually =Bc^2 exp(h.kT)/2h

    I think I correctly calculated the exp(h/kT) bit but I just can't figure out the rest of the equation on the RHS
    Thanks for looking
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