Dealing with an exponentially debilitating problem

1. Mar 10, 2008

redbaldyhead

I can't resolve v(cubed)/exp(v)-1
which is the RHS of an equation that has been sorted out of the left!
I am rather hoping that this becomes v(cubed)/v which simplifies to v^2.

Thanks

2. Mar 10, 2008

symbolipoint

What are you trying to express, and what are you trying to find? Are you starting with this:

$$$\frac{{v^3 }}{{e^v }} - 1$$$

3. Mar 10, 2008

redbaldyhead

Sorry for the delay in responding!
No it is the RHS of Planck's equation for B(v)T
The LHS as I have reduced it to =Bc^2/2H

4. Mar 10, 2008

redbaldyhead

Actually =Bc^2 exp(h.kT)/2h

I think I correctly calculated the exp(h/kT) bit but I just can't figure out the rest of the equation on the RHS
Thanks for looking

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