Decay contant of xenon and strontium

  • Thread starter Thread starter cowboi123
  • Start date Start date
  • Tags Tags
    Decay Xenon
AI Thread Summary
The discussion centers on calculating the time required for the ratio of strontium-90 to xenon-142 nuclei to reach 1.20*10^6, given their respective decay constants. The decay constant for xenon-142 is 0.462 s^-1, while for strontium-90, it is 7.85*10^-10 s^-1. Participants suggest using the formula N = N0 * e^(-kt) to derive equations for both isotopes and establish the desired ratio. The goal is to set the ratio equal to the calculated value to find the time. This approach will help solve the problem effectively.
cowboi123
Messages
2
Reaction score
0

Homework Statement



The decay constant of xenon-142 is 0.462(s^-1), and the decay constant of strontium-90 is 7.85*10^-10 (s^-1). Initially, a sample of radioactive waste material contains equal numbers of strontium-90 and xenon-142 nuclei.

Calculate the time taken for the ratio: number of strontium-90 nuclei/number of xenon-142 nuclei to become equal to 1.20*10^6.

Homework Equations



Not sure

The Attempt at a Solution



Not sure, please help!
 
Physics news on Phys.org
Have you seen the formula N=N0*e^(-kt)? Write out a formula for xenon, a formula for strontium, and a formula for the strontium:xenon ratio. The reason for doing this is that you know this ratio's numerical value and can set it equal to the formula.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top