Decomposing a Series Using Riemann's Rearrangement Theorem

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Homework Statement


I'm trying to compute the sum of the following series:

S=1+\frac{1}{4}-\frac{1}{16}-\frac{1}{64}+\frac{1}{256}


Homework Equations





The Attempt at a Solution


I'm not really sure how to begin this one. I know it probably involves Riemann's Rearrangement Theorem since this series is absolutely convergent.
 
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the_kid said:

Homework Statement


I'm trying to compute the sum of the following series:

S=1+\frac{1}{4}-\frac{1}{16}-\frac{1}{64}+\frac{1}{256}


Homework Equations





The Attempt at a Solution


I'm not really sure how to begin this one. I know it probably involves Riemann's Rearrangement Theorem since this series is absolutely convergent.

Are the successive signs really ++--+? What happens after that? Are you sure you copied the question correctly?

RGV
 
My apologies; I should have been clearer in my original post.

The signs are ++-- ++-- ...
 
Any help?
 
Okay, so I think that if you think about it as the sum of two sums, that will help...

think of the first sum as the sum of every odd indexed term, and the second sum as the sum of every even indexed term.

S1 = 1-1/16+1/256...
S2 = 1/4-1/64+1/(16*64)...

thus, the first sum will be

S1 = \sum(-1/16)n from n = 0 to ∞.

and the second, I'll let you figure out. but I think that this should help. (note, the second one needs a constant out front.

hope this helps!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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