Decomposition of hydrogen peroxide

AI Thread Summary
The discussion centers on determining the concentration of hydrogen peroxide during its decomposition with manganese(IV) oxide. The recommended method involves adding the reaction mixture to dilute sulfuric acid and titrating it with potassium permanganate. Dilute sulfuric acid is used to prevent hydrolysis reactions between the metal and water, ensuring that the titration accurately measures hydrogen peroxide concentration without interference from unwanted reactions. The conversation highlights the importance of using a suitable acid to maintain the integrity of the reaction.
Clari
Messages
62
Reaction score
0
For the decomposition of hydrogen peroxide in the presence of manganese(IV) oxide, what is the chemical method to determine the concentration of hydrogen peroxide, at different times?

The solution is: To add the reaction mixture in dilute sulphuric acid, and then titrate the reaction mixture with potassium permanganate.

please tell me why dilute sulphric acid is used. Thanks!
 
Chemistry news on Phys.org
This is an old thread, but I am still waiting for someone to help me with it. ^-^
 
I thought we already answered this question...several times. Perhaps it is to prevent the hydrolysis reaction of the metal with water, an acid base reaction between the metal and water. If you add a stronger acid than the metal, the former will react with the water instead of the metal.
 
It seems like a simple enough question: what is the solubility of epsom salt in water at 20°C? A graph or table showing how it varies with temperature would be a bonus. But upon searching the internet I have been unable to determine this with confidence. Wikipedia gives the value of 113g/100ml. But other sources disagree and I can't find a definitive source for the information. I even asked chatgpt but it couldn't be sure either. I thought, naively, that this would be easy to look up without...
I was introduced to the Octet Rule recently and make me wonder, why does 8 valence electrons or a full p orbital always make an element inert? What is so special with a full p orbital? Like take Calcium for an example, its outer orbital is filled but its only the s orbital thats filled so its still reactive not so much as the Alkaline metals but still pretty reactive. Can someone explain it to me? Thanks!!
Back
Top