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Decomposition potential and Gibbs Free Energy

  1. Jun 20, 2015 #1
    The decomposition potential is always higher than the theoretically determined potential by thermodynamics. E=η+Eeq where E is the decomposition potential, η is the overpotential and Eeq is the theoretically determined potential.

    However since the decomposition potential is higher doesn't it mean that the reaction is more spontaneous? Which is opposite to the original meaning of the equation.
  2. jcsd
  3. Jun 26, 2015 #2
    Thanks for the post! This is an automated courtesy bump. Sorry you aren't generating responses at the moment. Do you have any further information, come to any new conclusions or is it possible to reword the post?
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