- #1
sgstudent
- 739
- 3
The decomposition potential is always higher than the theoretically determined potential by thermodynamics. E=η+Eeq where E is the decomposition potential, η is the overpotential and Eeq is the theoretically determined potential.
However since the decomposition potential is higher doesn't it mean that the reaction is more spontaneous? Which is opposite to the original meaning of the equation.
However since the decomposition potential is higher doesn't it mean that the reaction is more spontaneous? Which is opposite to the original meaning of the equation.