Defenestration homework not going so well -_-

[liagee]

A ball is thrown horizontally from the top of
a building 53.8 m high. The ball strikes the
ground at a point 119 m from the base of the
building.
The acceleration of gravity is 9.8 m/s. The time (I got this answer and it's correct and all) is 3.3135sec.
(part 2 of 4) Find the initial velocity of the ball.
(part 3 of 4) Find the x component of its velocity just before it strikes the ground.
007 (part 4 of 4) 10.0 points
Find the y component of its velocity just before it strikes the ground.v_average = d/t

a = V_delta/t

v_f = v_i + at

I don't even know any others -_-

I tried to use vf^2 = vi^2 + 2ad?? It didn't work. I am really lost but if someone could tell me which formula (kinematics) to use that would be great.I already got the time (part 1 of 4) to equal 3.3135sec but despite using the right equations etc I can't get the other three parts.

 

[gneill]

The ball was thrown horizontally. How far did it travel horizontally? Over what time? What can change the horizontal velocity?

What's its initial y-velocity? What could change the y-velocity?

 

[liagee]

The ball was thrown horizontally. How far did it travel horizontally? Over what time? What can change the horizontal velocity?

What's its initial y-velocity? What could change the y-velocity?

Acceleration_g would change it, and I tried the answer (online homework) in both negative and positive?? The initial y-velocity goes unstated.

 

[gneill]

Acceleration_g would change it, and I tried the answer (online homework) in both negative and positive?? The initial y-velocity goes unstated.

Acceleration would change what in particular?

The ball was thrown horizontally. What does that mean for the x and y components of the initial velocity?

What equation describes the x-position with respect to time? How about the y-position?

 

[liagee]

Acceleration would change what in particular?

The ball was thrown horizontally. What does that mean for the x and y components of the initial velocity?

What equation describes the x-position with respect to time? How about the y-position?

Acceleration would change the velocity only in the y-direction. Acceleration and therefore velocity in the x-direction remain constant, with acceleration_x=0 m/s.

\Deltas=v_it + .5 (a)(t²)

Thanks so much!

 

[liagee]

Actually that didn't work either -___-

 

[gneill]

Actually that didn't work either -___-

Didn't work for what? You'll have to be more specific. There are several parts to the problem. What are you trying to find first?

 

[berkeman]

Sorry if I missed it. What's Defenestration?

 

[berkeman]

Sorry if I missed it. What's Defenestration?