Definite Integral Length of vector r(t)

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SUMMARY

The discussion focuses on evaluating the integral length of the vector function r(t) = [t, t^2] from t = 0 to t = 2. The correct approach involves calculating the arc length using the formula ∫ from 0 to 2 of √((dx/dt)² + (dy/dt)²) dt. Here, dx/dt = 1 and dy/dt = 2t, leading to the integral ∫ from 0 to 2 of √(1 + (2t)²) dt. This integral can be solved to find the total length of the curve defined by r(t).

PREREQUISITES
  • Understanding of vector functions in R²
  • Knowledge of arc length formulas
  • Familiarity with integration techniques
  • Basic calculus concepts, including derivatives
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  • Study the derivation of the arc length formula for vector functions
  • Learn how to compute integrals involving square roots of polynomials
  • Explore applications of arc length in physics and engineering
  • Investigate numerical methods for approximating integrals
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Students studying calculus, particularly those focusing on vector functions and arc length calculations, as well as educators looking for examples of integral applications in geometry.

jimbo71
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Homework Statement


Evaluate the integral length of r(t)=[tihat +t^2jhat]dt from 0 to 2


Homework Equations





The Attempt at a Solution


I think I should find the length of r(t) first which would be sqrt(t^2ihat+t^4jhat). However I'm not sure how I would integrate sqrt(t^2ihat+t^4jhat).
 
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You can also write r(t) as (x(t), y(t)), where it's understood that this is a vector in R^2. Here x(t) = t and y(t) = t^2. For arc length between t = 0 and t = 2, your integral should be:
[tex]\int_0^2 \sqrt{(dx/dt)^2 + (dy/dt)^2} dt[/tex]
 

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