The discussion revolves around evaluating the definite integral of a trigonometric function, specifically ∫tan^5(x) sec(x) dx from 0 to π/3. Participants are exploring methods to manipulate the integrand for easier integration.
The discussion is active, with participants offering different approaches to tackle the integral. One participant indicates that a suggested method was effective, but there is no clear consensus on a single approach yet.
Participants are working within the constraints of standard trigonometric identities and integration techniques, and there is an emphasis on finding a suitable form for the integral without providing a complete solution.
Finding the anti-derivative of tan5(x) sec(x) is a lot like solving your previous tread.johnhuntsman said:π/3
∫tan^5 x sec x
0
I want to split the tan^5 x into a (sec^2 x - 1) but I only have sec x. So I'm a bit stuck. Help is appreciated.