Definite Integral of a Trig Fxn

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johnhuntsman
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π/3
∫tan^5 x sec x
0

I want to split the tan^5 x into a (sec^2 x - 1) but I only have sec x. So I'm a bit stuck. Help is appreciated.
 
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johnhuntsman said:
π/3
∫tan^5 x sec x
0

I want to split the tan^5 x into a (sec^2 x - 1) but I only have sec x. So I'm a bit stuck. Help is appreciated.
Finding the anti-derivative of tan5(x) sec(x) is a lot like solving your previous tread.

Split tan5(x) into tan4(x) tan(x) then use the trig identity which will change tan4(x)  into a combination of secant functions.
 
^ That did the trick. Thank you : D